20x^2+29xy+5y^2=0

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Solution for 20x^2+29xy+5y^2=0 equation:


Simplifying
20x2 + 29xy + 5y2 = 0

Reorder the terms:
29xy + 20x2 + 5y2 = 0

Solving
29xy + 20x2 + 5y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(5x + y)(4x + 5y) = 0

Subproblem 1

Set the factor '(5x + y)' equal to zero and attempt to solve: Simplifying 5x + y = 0 Solving 5x + y = 0 Move all terms containing x to the left, all other terms to the right. Add '-1y' to each side of the equation. 5x + y + -1y = 0 + -1y Combine like terms: y + -1y = 0 5x + 0 = 0 + -1y 5x = 0 + -1y Remove the zero: 5x = -1y Divide each side by '5'. x = -0.2y Simplifying x = -0.2y

Subproblem 2

Set the factor '(4x + 5y)' equal to zero and attempt to solve: Simplifying 4x + 5y = 0 Solving 4x + 5y = 0 Move all terms containing x to the left, all other terms to the right. Add '-5y' to each side of the equation. 4x + 5y + -5y = 0 + -5y Combine like terms: 5y + -5y = 0 4x + 0 = 0 + -5y 4x = 0 + -5y Remove the zero: 4x = -5y Divide each side by '4'. x = -1.25y Simplifying x = -1.25y

Solution

x = {-0.2y, -1.25y}

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